Age, Biography and Wiki

Dewey Skipworth (Charles Dewey Skipworth) was born on 28 July, 1899 in Alabama, USA, is an Actor. Discover Dewey Skipworth's Biography, Age, Height, Physical Stats, Dating/Affairs, Family and career updates. Learn How rich is He in this year and how He spends money? Also learn how He earned most of Dewey Skipworth networth?

Popular As Charles Dewey Skipworth
Occupation actor
Age 60 years old
Zodiac Sign Leo
Born 28 July 1899
Birthday 28 July
Birthplace Alabama, USA
Date of death 19 August, 1959
Died Place Los Angeles, California, USA
Nationality United States

We recommend you to check the complete list of Famous People born on 28 July. He is a member of famous Actor with the age 60 years old group.

Dewey Skipworth Height, Weight & Measurements

At 60 years old, Dewey Skipworth height not available right now. We will update Dewey Skipworth's Height, weight, Body Measurements, Eye Color, Hair Color, Shoe & Dress size soon as possible.

Physical Status
Height Not Available
Weight Not Available
Body Measurements Not Available
Eye Color Not Available
Hair Color Not Available

Dating & Relationship status

He is currently single. He is not dating anyone. We don't have much information about He's past relationship and any previous engaged. According to our Database, He has no children.

Family
Parents Not Available
Wife Not Available
Sibling Not Available
Children Not Available

Dewey Skipworth Net Worth

His net worth has been growing significantly in 2022-2023. So, how much is Dewey Skipworth worth at the age of 60 years old? Dewey Skipworth’s income source is mostly from being a successful Actor. He is from United States. We have estimated Dewey Skipworth's net worth , money, salary, income, and assets.

Net Worth in 2023 $1 Million - $5 Million
Salary in 2023 Under Review
Net Worth in 2022 Pending
Salary in 2022 Under Review
House Not Available
Cars Not Available
Source of Income Actor

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Timeline

1936

He was an actor, known for Ace Drummond (1936).

1899

Dewey Skipworth was born on July 28, 1899 in Alabama, USA as Charles Dewey Skipworth.