Age, Biography and Wiki

Sybil Grove (Sybil Marian Westmacott) was born on 4 October, 1891 in Teddington, Middlesex, England, UK, is an Actress. Discover Sybil Grove's Biography, Age, Height, Physical Stats, Dating/Affairs, Family and career updates. Learn How rich is She in this year and how She spends money? Also learn how She earned most of Sybil Grove networth?

Popular As Sybil Marian Westmacott
Occupation actress
Age 130 years old
Zodiac Sign Libra
Born 4 October 1891
Birthday 4 October
Birthplace Teddington, Middlesex, England, UK
Nationality United Kingdom

We recommend you to check the complete list of Famous People born on 4 October. She is a member of famous Actress with the age 130 years old group.

Sybil Grove Height, Weight & Measurements

At 130 years old, Sybil Grove height is 5' 8" (1.73 m) .

Physical Status
Height 5' 8" (1.73 m)
Weight Not Available
Body Measurements Not Available
Eye Color Not Available
Hair Color Not Available

Who Is Sybil Grove's Husband?

Her husband is George Christopher Wingrove (March 1918 - ?) ( his death), Francis Bernard Secker (? - 1962) ( his death)

Family
Parents Not Available
Husband George Christopher Wingrove (March 1918 - ?) ( his death), Francis Bernard Secker (? - 1962) ( his death)
Sibling Not Available
Children Not Available

Sybil Grove Net Worth

Her net worth has been growing significantly in 2022-2023. So, how much is Sybil Grove worth at the age of 130 years old? Sybil Grove’s income source is mostly from being a successful Actress. She is from United Kingdom. We have estimated Sybil Grove's net worth , money, salary, income, and assets.

Net Worth in 2023 $1 Million - $5 Million
Salary in 2023 Under Review
Net Worth in 2022 Pending
Salary in 2022 Under Review
House Not Available
Cars Not Available
Source of Income Actress

Sybil Grove Social Network

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Timeline

1930

She is an actress, known for Let Us Be Gay (1930), The Man from Toronto (1933) and C. O. D.

1891

Sybil Grove was born on October 4, 1891 in Teddington, Middlesex, England as Sybil Marian Westmacott.